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TS EAMCET · Maths · Quadratic Equation

If \(\alpha\) and \(\beta\) are the roots of the equation \(a x^2+b x+c=0\) and the equation having roots \(\frac{1-\alpha}{\alpha}\) and \(\frac{1-\beta}{\beta}\) is \(p x^2+q x+r=0\), then \(r=\)

  1. A \(a+2 b\)
  2. B \(a b+b c+c a\)
  3. C \(a+b+c\)
  4. D \(a b c\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(a+b+c\)

Step-by-step Solution

Detailed explanation

We have, \(\alpha, \beta\) are the roots of the equations \(a x^2+b x+c=0\) \[ \therefore \quad \alpha+\beta=-\frac{b}{a}, \alpha \beta=\frac{c}{a} \] Equations whose roots are \(\frac{1-\alpha}{\alpha}\) and \(\frac{1-\beta}{\beta}\) are…
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