TS EAMCET · Maths · Quadratic Equation
The value of \(\sqrt{42+\sqrt{42+\sqrt{42+\ldots \ldots .}}}\) is equal
- A \(7\)
- B \(-6\)
- C \(5\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(7\)
Step-by-step Solution
Detailed explanation
Let \(y=\sqrt{42+\sqrt{42+\sqrt{42+\ldots}}}\) \[ \Rightarrow \quad y=\sqrt{42+y} \] On squaring both sides, we get \[ \begin{aligned} & y^2=42+y \\ & \Rightarrow \quad y^2-y-42=0 \\ & \end{aligned} \]…
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