JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
When kinetic energy of a body becomes \(36\) times of its original value, the percentage increase in the momentum of the body will be _______.
- A \(500 \%\)
- B \(600 \%\)
- C \(6 \%\)
- D \(60 \%\)
Answer & Solution
Correct Answer
(A) \(500 \%\)
Step-by-step Solution
Detailed explanation
\(\text { Kinetic energy }(\mathrm{K})=\frac{\mathrm{P}^2}{2 \mathrm{~m}}\) \(\Rightarrow \mathrm{P}=\sqrt{2 \mathrm{mK}}\) \(\text { If } \mathrm{K}_{\mathrm{f}}=36 \mathrm{~K}_{\mathrm{i}}\) \(\text { So, } \mathrm{P}_{\mathrm{f}}=6 \mathrm{P}_{\mathrm{i}}\)…
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