JEE Mains · Physics · STD 11 - 11. thermodynamics
Thermodynamic process is shown below on a \(P-V\) diagram for one mole of an ideal gas. If \(V _{2}=2 V _{1}\) then the ratio of temperature \(T _{2} / T _{1}\) is ...... .
- A \(\frac{1}{2}\)
- B \(2\)
- C \(\sqrt{2}\)
- D \(\frac{1}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{2}\)
Step-by-step Solution
Detailed explanation
\(PV ^{1 / 2}= c\) \(\frac{ nRT }{ V } V ^{1 / 2}= c\) \(T = c ^{1} V ^{1 / 2}\) \(\frac{ T _{2}}{ T _{1}}=\left(\frac{ V _{2}}{ V _{1}}\right)^{1 / 2}=\left(\frac{2 V _{1}}{ V _{1}}\right)^{1 / 2}\) \(\frac{ T _{2}}{ T _{1}}=\sqrt{2}\)
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