JEE Mains · Physics · STD 12 - Nuclei
- JEE Mains 2024
- Medium
- MCQ
Binding energy of a certain nucleus is \(18 \times 10^8 J\). How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus?
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(20 \mu g\)
Step-by-step Solution
Detailed explanation
\(\Delta mc ^2=18 \times 10^8\)
\(\Delta m \times 9 \times 10^{16}=18 \times 10^8\)
\(\Delta m =2 \times 10^{-8} kg=20 \mu g\)
\(\Delta m \times 9 \times 10^{16}=18 \times 10^8\)
\(\Delta m =2 \times 10^{-8} kg=20 \mu g\)
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