JEE Mains · Physics · STD 12 - 13. Nuclei
Binding energy of a certain nucleus is \(18 \times 10^8 J\). How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus?
- A \(10 \mu g\)
- B \(20 \mu g\)
- C \(0.2 \mu g\)
- D \(2 \mu g\)
Answer & Solution
Correct Answer
(B) \(20 \mu g\)
Step-by-step Solution
Detailed explanation
\(\Delta mc ^2=18 \times 10^8\) \(\Delta m \times 9 \times 10^{16}=18 \times 10^8\) \(\Delta m =2 \times 10^{-8} kg=20 \mu g\)
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