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JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
  • JEE Mains 2022
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  • MCQ

A copper block of mass \(5.0\, kg\) is heated to a temperature of \(500^{\circ} C\) and is placed on a large ice block. What is the maximum amount of ice (ઇન \(kg\)) that can melt? [Specific heat of copper: \(0.39\, Jg ^{-1 \circ} C ^{-1}\) and latent heat of fusion of water : \(335 \,J g ^{-1}\) ]

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Answer & Solution

Correct Answer

(C) \(2.9\)

Step-by-step Solution

Detailed explanation

Heat given by block to get \(0\,^{\circ} C\) temperature

\(\Delta Q _{1}=5 \times\left(0.39 \times 10^{3}\right) \times(500-0)\)

\(=975 \times 10^{3} J\)

Heat absorbed by ice to melt \(m\) mass

\(\Delta Q _{2}= m \times\left(335 \times 10^{3}\right) J\)

\(\Delta Q _{1}=\Delta Q _{2}\)

\(m \times\left(335 \times 10^{3}\right)=975 \times 10^{3}\)

\(m =\frac{975}{335}=2.910\, kg\)

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