JEE Mains · Physics · STD 11 - 10.1, thermonetry,thermal expansion and calorimetry
A copper block of mass \(5.0\, kg\) is heated to a temperature of \(500^{\circ} C\) and is placed on a large ice block. What is the maximum amount of ice (ઇન \(kg\)) that can melt? [Specific heat of copper: \(0.39\, Jg ^{-1 \circ} C ^{-1}\) and latent heat of fusion of water : \(335 \,J g ^{-1}\) ]
- A \(1.5\)
- B \(5.8\)
- C \(2.9\)
- D \(3.8\)
Answer & Solution
Correct Answer
(C) \(2.9\)
Step-by-step Solution
Detailed explanation
Heat given by block to get \(0\,^{\circ} C\) temperature \(\Delta Q _{1}=5 \times\left(0.39 \times 10^{3}\right) \times(500-0)\) \(=975 \times 10^{3} J\) Heat absorbed by ice to melt \(m\) mass \(\Delta Q _{2}= m \times\left(335 \times 10^{3}\right) J\)…
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