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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
When a rubber ball is taken to a depth of \(......\,{m}\) in deep sea, its volume decreases by \(0.5\, \%\) (The bulk modulus of rubber \(=9.8 \times 10^{8}\, {Nm}^{-2}\) Density of sea water \(=10^{3} {kgm}^{-3}\) \(\left.{g}=9.8\, {m} / {s}^{2}\right)\)
- A \(800\)
- B \(5000\)
- C \(500\)
- D \(100\)
Answer & Solution
Correct Answer
(C) \(500\)
Step-by-step Solution
Detailed explanation
\(B=-\frac{\Delta P}{\left(\frac{\Delta V}{V}\right)}=-\frac{\rho g h}{\left(\frac{\Delta V}{V}\right)}\) \(-\frac{B \frac{\Delta V}{V}}{\rho g}=h\) \(\frac{9.8 \times 10^{8} \times 0.5}{100 \times 10^{3} \times 9.8}=h\) \(h=500\)
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