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JEE Mains · Physics · STD 11 - Fluid mechanics
  • JEE Mains 2021
  • Medium
  • Numerical

When a rubber ball is taken to a depth of \(......\,{m}\) in deep sea, its volume decreases by \(0.5\, \%\) (The bulk modulus of rubber \(=9.8 \times 10^{8}\, {Nm}^{-2}\) Density of sea water \(=10^{3} {kgm}^{-3}\) \(\left.{g}=9.8\, {m} / {s}^{2}\right)\)

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Answer & Solution

Correct Answer

(C) \(500\)

Step-by-step Solution

Detailed explanation

\(B=-\frac{\Delta P}{\left(\frac{\Delta V}{V}\right)}=-\frac{\rho g h}{\left(\frac{\Delta V}{V}\right)}\)

\(-\frac{B \frac{\Delta V}{V}}{\rho g}=h\)

\(\frac{9.8 \times 10^{8} \times 0.5}{100 \times 10^{3} \times 9.8}=h\)

\(h=500\)

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