JEE Mains · Physics · STD 12 - 3. current electricity
A current of \(15\,mA\) flows in the circuit as shown in figure. The value of potential difference between the points \(A\) and \(B\) will be \(...\,V\)
- A \(50\)
- B \(75\)
- C \(150\)
- D \(275\)
Answer & Solution
Correct Answer
(D) \(275\)
Step-by-step Solution
Detailed explanation
\(i_{1}=\frac{5}{10+5} \times 15 mA =5 mA\) \(V _{ A }-5 i -10 i _{1}-10 i = V _{ B }\) \(V _{ A }- V _{ B }=75+50+150=275\,V\)
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