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JEE Mains · Physics · STD 11 - 9.1 fluid mechanics

The average mass of rain drops is \(3.0\times10^{-5}\, kg\) and their avarage terminal velocity is \(9\, m/s\). Calculate the energy transferred by rain to each square metre of the surface at a place which receives \(100\, cm\) of rain in a year

  1. A \(3.5\times10^5\, J\)
  2. B \(4.05\times10^4\, J\)
  3. C \(3.0\times10^5\, J\)
  4. D \(9.0\times10^4\, J\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(4.05\times10^4\, J\)

Step-by-step Solution

Detailed explanation

Total volume of rain drops, recrived \(100\,cm\) in a year by area \(1\,m^2\) \( = 1{m^2} \times \frac{{100}}{{100}}m = 1\,{m^3}\) As we know, density of water, \(d = {10^3}\,kg/{m^3}\) Therefore, mass of this volume of water, \(M = d \times v = {10^3} \times 1 = {10^3}\,kg\)…
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