JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
Glycerine of density \(1.25 \times 10^3\,kg\,m ^{-3}\) is flowing through the conical section of pipe. The area of cross-section of the pipe at its ends is \(10\,cm ^2\) and \(5\,cm ^2\) and pressure drop across its length is \(3\,Nm ^{-2}\). The rate of flow of glycerine through the pipe is \(x \times 10^{-5} m ^3 s ^{-1}\). The value of \(x\) is \(..............\).

- A \(2\)
- B \(6\)
- C \(8\)
- D \(4\)
Answer & Solution
Correct Answer
(D) \(4\)
Step-by-step Solution
Detailed explanation
\(\Delta P = P _1- P _2=3 N / m ^2 \text { (given) }\) By continuity \(eq ^{ n }\) \(A _1 v _1= A _2 v _2\) \(\therefore \quad v_1=\frac{A_2}{A_1} v_2-(1)\) By Bernoulli's equation. \(P _1+\frac{1}{2} \rho v _1{ }^2= P _2+\frac{1}{2} \rho v _2{ }^2\)…
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