JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2022
- Hard
- MCQ
What percentage of kinetic energy of a moving particle is transferred to a stationary particle when it strikes the stationary particle of \(5\) times its mass? (Assume the collision to be head-on elastic collision)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(55.5\)
Step-by-step Solution
Detailed explanation
Velocity after collision
\(V_{2}=\frac{\left(m_{2}-m_{1}\right) u_{2}+2 m_{1} u_{1}}{m_{1}+m_{2}}\)
\(V_{2}=\frac{(5 m-m) 0+2 m \cdot u_{0}}{m+5 m}=\frac{u_{0}}{3}\)
\(\% \Delta K E=\frac{\frac{1}{2} 5 m\left(\frac{u_{0}}{3}\right)^{2}-0}{\frac{1}{2} m u_{0}^{2}} \times 100\)
\(=\frac{5 u_{0}^{2}}{9 u_{0}^{2}} \times 100=\frac{500}{9}=55.6 \%\)
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