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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases

For an ideal gas the instantaneous change in pressure \('{p} '\) with volume \('v'\) is given by the equation \(\frac{{dp}}{{dv}}=-{ap} .\) If \({p}={p}_{0}\) at \({v}=0\) is the given boundary condition, then the maximum temperature one mole of gas can attain is : (Here \({R}\) is the gas constant)

  1. A \(\frac{{p}_{0}}{{aeR}}\)
  2. B \(\frac{a p_{0}}{e R}\)
  3. C \(infinity\)
  4. D \(0^{\circ} {C}\)
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Answer & Solution

Correct Answer

(A) \(\frac{{p}_{0}}{{aeR}}\)

Step-by-step Solution

Detailed explanation

\(\int_{p_{0}}^{p} \frac{d p}{P}=-a \int_{0}^{v} d v\) \(\ell n\left(\frac{p}{p_{0}}\right)=-a v\) \(p=p_{0} e^{-a v}\) For temperature maximum p-v product should be maximum \({T}=\frac{{pv}}{{n} {R}}=\frac{{p}_{0} {ve}^{-{av}}}{{R}}\)…
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