JEE Mains · Maths · STD 11 - 9. straight line
The distance of the point \((2,3)\) from the line \(2 \mathrm{x}-\) \(3 \mathrm{y}+28=0\), measured parallel to the line \(\sqrt{3} \mathrm{x}-\mathrm{y}+1=0\), is equal to
- A \(4 \sqrt{2}\)
- B \(6 \sqrt{3}\)
- C \(3+4 \sqrt{2}\)
- D \(4+6 \sqrt{3}\)
Answer & Solution
Correct Answer
(D) \(4+6 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
Writing \(\mathrm{P}\) in terms of parametric co-ordinates \(2+r\) \( \cos \theta, 3+\mathrm{r} \sin \theta \text { as } \tan \theta=\sqrt{3} \) \( \mathrm{P}\left(2+\frac{\mathrm{r}}{2}, 3+\frac{\sqrt{3} \mathrm{r}}{2}\right)\) \(P\) must satisfy…
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