JEE Mains · Maths · STD 12 - 8. Application and integration
The area bounded by the curves \(y=|x-1|+|x-2|\) and \(y =3\) is equal to
- A \(3\)
- B \(4\)
- C \(5\)
- D \(6\)
Answer & Solution
Correct Answer
(B) \(4\)
Step-by-step Solution
Detailed explanation
\(y=|x-1|+|x-2| \text { and } y=3\) \(\therefore \text { Required area }=\frac{1}{2}(1+3) \times 2=4\)
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