JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2026
- Hard
- Numerical
A gas of certain mass filled in a closed cylinder at a pressure of 3.23 kPa has temperature \(50^{\circ} C\). The gas is now heated to double its temperature. The modified pressure is _________ Pa .
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) 3730
Step-by-step Solution
Detailed explanation
As per NTA
\(V =\) constant
so \(P \propto T\)
\(T _{ i }=50^{\circ} C =323 K\)
\(T _{ f }=100^{\circ} C =373 K\)
\(\Rightarrow \frac{ P _{ f }}{ P _{ i }}=\frac{ T _{ f }}{ T _{ i }}\)
\(\Rightarrow \frac{ P _{ f }}{3.23 kPa }=\frac{373}{323}\)
\(\Rightarrow P _{ f }=3730 Pa\)
\(V =\) constant
so \(P \propto T\)
\(T _{ i }=50^{\circ} C =323 K\)
\(T _{ f }=100^{\circ} C =373 K\)
\(\Rightarrow \frac{ P _{ f }}{ P _{ i }}=\frac{ T _{ f }}{ T _{ i }}\)
\(\Rightarrow \frac{ P _{ f }}{3.23 kPa }=\frac{373}{323}\)
\(\Rightarrow P _{ f }=3730 Pa\)
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