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JEE Mains · Physics · STD 11 - Thermodynamics
  • JEE Mains 2025
  • Easy
  • MCQ


Using the given \(\mathrm{P}-\mathrm{V}\) diagram, the work done by an ideal gas along the path ABCD is :

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Answer & Solution

Correct Answer

(C) \(-3 \mathrm{P}_0 \mathrm{~V}_0\)

Step-by-step Solution

Detailed explanation


Area under graph will be magnitude of graph and being counterclockwise graph it would be negative
\(\begin{aligned}
& \text { Area }=2 P_0 \times V_0+P_0 V_0=3 P_0 V_0 \\
& \mathrm{~W}=-3 P_0 V_0
\end{aligned}\)