JEE Mains · Physics · STD 12 - 2. Electric potential and capacitance
A capacitor, \(C_1=6 \mu \mathrm{~F}\) is charged to a potential difference of \(\mathrm{V}_0=5 \mathrm{~V}\) using a 5 V battery. The battery is removed and another capacitor, \(\mathrm{C}_2=12 \mu \mathrm{~F}\) is inserted in place of the battery. When the switch 'S' is closed, the charge flows between the capacitors for some time until equilibrium condition is reached. What are the charges \(\left(q_1\right.\) and \(\left.q_2\right)\) on the capacitors \(C_1\) and \(C_2\) when equilibrium condition is reached.
- A \(q_1=10 \mu \mathrm{C}, \mathrm{q}_2=20 \mu \mathrm{C}\)
- B \(\mathrm{q}_1=30 \mu \mathrm{C}, \mathrm{q}_2=15 \mu \mathrm{C}\)
- C \(\mathrm{q}_1=20 \mu \mathrm{C}, \mathrm{q}_2=10 \mu \mathrm{C}\)
- D \(\mathrm{q}_1=15 \mu \mathrm{C}, \mathrm{q}_2=30 \mu \mathrm{C}\)
Answer & Solution
Correct Answer
(A) \(q_1=10 \mu \mathrm{C}, \mathrm{q}_2=20 \mu \mathrm{C}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{q}_1^{\prime}=6 \times 5=30 \mu \mathrm{C}\) Finally…
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