JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(\alpha\) be the area of the larger region bounded by the curve \(y ^2=8 x\) and the lines \(y = x\) and \(x =2\), which lies in the first quadrant. Then the value of \(3 \alpha\) is equal to \(..............\).
- A \(20\)
- B \(21\)
- C \(23\)
- D \(22\)
Answer & Solution
Correct Answer
(D) \(22\)
Step-by-step Solution
Detailed explanation
\(y=x\) \(y^2=8 x\) Solving it \(x ^2=8 x\) \(x=0,8\) \(y=0,8\) \(x=2\) will intersect occur at \(y^2=16 \Rightarrow \quad y=\pm 4\) Area of shaded \(=\int \limits_2^8(\sqrt{8 x}-x) d x=\int_2^8(2 \sqrt{2} \sqrt{x}-x) d x\)…
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