JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A particle of mass \(m\) with an initial velocity \(u\hat i\) collides perfectly elastically with a mass \(3m\) at rest. It moves with a velocity \(v\hat j\) after collision, then, \(v\) is given by
- A \(v=\sqrt{\frac{2}{3}} u\)
- B \(v =\frac{1}{\sqrt{6}} u\)
- C \(v=\frac{u}{\sqrt{3}}\)
- D \(v=\frac{u}{\sqrt{2}}\)
Answer & Solution
Correct Answer
(D) \(v=\frac{u}{\sqrt{2}}\)
Step-by-step Solution
Detailed explanation
From momentum conservation \(\overrightarrow{ P }_{ i }=\overrightarrow{ P }_{ f }\) \(m ( ui )+3 m ( D )= mvj +3 m \overline{ v }_{2}\) \(mui - mvj =3 m \overline{ v }_{1}\) \(\bar{v}_{1}=\frac{u i-v j}{3}\) or \(\left| v _{1}\right|=\frac{\sqrt{ u ^{2}+ v ^{2}}}{3}\) or…
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