JEE Mains · Physics · STD 11 - Transmission of heat
- JEE Mains 2021
- Hard
- MCQ
Two thin metallic spherical shells of radii \({r}_{1}\) and \({r}_{2}\) \(\left({r}_{1}<{r}_{2}\right)\) are placed with their centres coinciding. A material of thermal conductivity \({K}\) is filled in the space between the shells. The inner shell is maintained at temperature \(\theta_{1}\) and the outer shell at temperature \(\theta_{2}\left(\theta_{1}<\theta_{2}\right)\). The rate at which heat flows radially through the material is :-
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(\frac{4 \pi {Kr}_{1} {r}_{2}\left(\theta_{2}-\theta_{1}\right)}{{r}_{2}-{r}_{1}}\)
Step-by-step Solution
Detailed explanation
Thermal resistance of spherical sheet of thicleness \(dr\) and radius \(r\) is
\({d} {R}=\frac{{dr}}{{K}\left(4 \pi {r}^{2}\right)}\)
\({R}=\int_{{r}_{1}}^{{r}_{2}} \frac{{dr}}{{K}\left(4 \pi {r}^{2}\right)}\)
\({R}=\frac{1}{4 \pi {K}}\left(\frac{1}{{r}_{1}}-\frac{1}{{r}_{2}}\right)=\frac{1}{4 \pi {K}}\left(\frac{{I}_{2}-{r}_{1}}{{r}_{1} {I}_{2}}\right)\)
Thermal current (i) \(=\frac{\theta_{2}-\theta_{1}}{R}\)
\({i} =\frac{4 \pi {Kr}_{1} {r}_{2}\left(\theta_{2}-\theta_{1}\right)}{{r}_{2}-{r}_{1}}\)
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