JEE Mains · Maths · STD 11 - 14. probability
If three of the six vertices of a regular hexagon are chosen at random, then the probability that the triangle formed with these chosen vertices is equilateral is
- A \(\frac{3}{{10}}\)
- B \(\frac{1}{{5}}\)
- C \(\frac{1}{{10}}\)
- D \(\frac{3}{{20}}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{{10}}\)
Step-by-step Solution
Detailed explanation
Only two equilateral triangle are possible \(A_{1} A_{3} A_{5}\) and \(A_{2} A_{5} A_{6}\) \(\frac{2}{^{6} \mathrm{C}_{3}}=\frac{2}{20}=\frac{1}{10}\)
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