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JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A projectile of mass \(M\) is fired so that the horizontal range is \(4\, km\). At the highest point the projectile explodes in two parts of masses \(M/4\) and \(3M/4\) respectively and the heavier part starts falling down vertically with zero initial speed. The horizontal range (distance from point of firing) of the lighter part is .................. \(\mathrm{km}\)
- A \(16\)
- B \(1\)
- C \(10\)
- D \(2\)
Answer & Solution
Correct Answer
(C) \(10\)
Step-by-step Solution
Detailed explanation
\(OQ=4\;km\) \(QR=x\;km\) The centre of mass will hit the ground at point \(Q\). As the haviour mass comes to rest after bracking \({x_{cm}} = \frac{{{m_1}{x_1} + {m_2}{x_2}}}{{{m_1} + {m_2}}}\) \(\;Here\;{m_{1\;}} = \frac{{3M}}{4},{m_{2\;}} = \frac{M}{4},\;\)…
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