JEE Mains · Maths · STD 12 - 5. continuity and differentiation
If the function \(f(x)=\frac{1}{x} \log _{e}(\frac{1+\frac{x}{a}}{1-\frac{x}{b}}) , \quad x<0\) \(\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad k \quad, \quad x=0\) \(\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\frac{\cos ^{2} x-\sin ^{2} x-1}{\sqrt{x^{2}+1}-1} ,\,\,\, x>0\) is continuous at \(x=0\), then \(\frac{1}{a}+\frac{1}{b}+\frac{4}{k}\) is equal to :
- A \(-5\)
- B \(5\)
- C \(-4\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(-5\)
Step-by-step Solution
Detailed explanation
If \(f(\mathrm{x})\) is continuous at \(\mathrm{x}=0, \mathrm{RHL}=\mathrm{LHL}=f(0)\) \(\lim _{x \rightarrow 0^{+}} f(x)=\lim _{x \rightarrow 0^{+}} \frac{\cos ^{2} x-\sin ^{2} x-1}{\sqrt{x^{2}+1}-1} \cdot \frac{\sqrt{x^{2}+1}+1}{\sqrt{x^{2}+1}+1}\) (Rationalisation)…
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