JEE Mains · Physics · STD 11 - 3.2 motion in plane
Two projectiles are projected at \(30^{\circ}\) and \(60^{\circ}\) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
- A \(2: \sqrt{3}\)
- B \(\sqrt{3}: 1\)
- C \(1: 3\)
- D \(1: \sqrt{3}\)
Answer & Solution
Correct Answer
(C) \(1: 3\)
Step-by-step Solution
Detailed explanation
\(H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }\) \(\frac{ H _1}{ H _2}=\frac{\sin ^2 \theta_1}{\sin ^2 \theta_2}=\frac{1}{3}\)
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