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JEE Mains · Physics · STD 11 - 13. oscillations

Two waves executing simple harmonic motion travelling in the same direction with same amplitude and frequency are superimposed. The resultant amplitude is equal to the \(\sqrt{3}\) times of amplitude of individual motions. The phase difference between the two motions is \(.....(degree)\)

  1. A \(55\)
  2. B \(56\)
  3. C \(60\)
  4. D \(53\)
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Answer & Solution

Correct Answer

(C) \(60\)

Step-by-step Solution

Detailed explanation

\(A _{\text {resultrant }}=\sqrt{ A _{1}^{2}+ A _{2}^{2}+2 A _{1} A _{2} \cos \phi}\) \(\sqrt{3} A =\sqrt{ A ^{2}+ A ^{2}+2 A ^{2} \cos \phi}\) \(3 A ^{2}=2 A ^{2}+2 A ^{2} \cos \phi\) \(\cos \phi=\frac{1}{2}\) \(\therefore \phi=60^{\circ}\)…
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