JEE Mains · Physics · STD 11 - Gravitation
- JEE Mains 2022
- Medium
- MCQ
Two satellites \(A\) and \(B\) having masses in the ratio \(4: 3\) are revolving in circular orbits of radii \(3\,r\) and \(4\,r\) respectively around the earth. The ratio of total mechanical energy of \(A\) to \(B\) is.
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(16: 9\)
Step-by-step Solution
Detailed explanation
Given that \(\frac{m_{1}}{m_{2}}=\frac{4}{3}, \frac{r_{1}}{r_{2}}=\frac{3}{4}\)
Now \(T E=\frac{1}{2} mv ^{2}+\left(\frac{- GMm }{ r }\right)\)
but \(\frac{ mv ^{2}}{ r }=\frac{ GMm }{ r ^{2}} \Rightarrow mv ^{2}=\frac{ GMm }{ r }\)
\(\Rightarrow TE =-\frac{ GMm }{2 r } \propto \frac{ m }{ r }\)
\(\frac{T E_{1}}{T_{2}}=\frac{m_{1}}{m_{2}} \cdot \frac{r_{2}}{r_{1}}=\frac{4}{3} \times \frac{4}{3}=\frac{16}{9}\)
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