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JEE Mains · Physics · STD 11 - 7. gravitation

Two satellites \(A\) and \(B\) having masses in the ratio \(4: 3\) are revolving in circular orbits of radii \(3\,r\) and \(4\,r\) respectively around the earth. The ratio of total mechanical energy of \(A\) to \(B\) is.

  1. A \(9: 16\)
  2. B \(16: 9\)
  3. C \(1: 1\)
  4. D \(4: 3\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(16: 9\)

Step-by-step Solution

Detailed explanation

Given that \(\frac{m_{1}}{m_{2}}=\frac{4}{3}, \frac{r_{1}}{r_{2}}=\frac{3}{4}\) Now \(T E=\frac{1}{2} mv ^{2}+\left(\frac{- GMm }{ r }\right)\) but \(\frac{ mv ^{2}}{ r }=\frac{ GMm }{ r ^{2}} \Rightarrow mv ^{2}=\frac{ GMm }{ r }\)…
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