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JEE Mains · Physics · STD 11 - 1. units,dimensions and measurement

\(\left(P+\frac{a}{V^2}\right)(V-b)=R T\) represents the equation of state of some gases. Where \(P\) is the pressure, \(V\) is the volume, \(T\) is the temperature and \(a, b, R\) are the constants. The physical quantity, which has dimensional formula as that of \(\frac{b^2}{a}\), will be

  1. A Bulk modulus
  2. B Modulus of rigidity
  3. C Compressibility
  4. D Energy density
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Answer & Solution

Correct Answer

(C) Compressibility

Step-by-step Solution

Detailed explanation

\({[b]=[V]}\) \(\left[\frac{a}{b^2}\right]=[P] \quad \therefore \quad\left[\frac{b^2}{a}\right]=\frac{1}{[P]}=\frac{1}{[B]}=[K]\)
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