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JEE Mains · Physics · STD 12 -7. Alternating current

A capacitor of capacitance \(500\,\mu F\) is charged completely using a dc supply of \(100\,V\). It is now connected to an inductor of inductance \(50\,mH\) to form an \(LC\) circuit. The maximum current in \(LC\) circuit will be \(.........A\).

  1. A \(10\)
  2. B \(1\)
  3. C \(0\)
  4. D \(100\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(10\)

Step-by-step Solution

Detailed explanation

Energy stored in capacitor \(=\frac{1}{2} CV ^{2}=\frac{1}{2} 500 \times 10^{-6} \times 10^{4}\) \(=\frac{5}{2}\,J\) Current will be maximum when whole energy of capacitor becomes energy of inductor. \(\frac{1}{2} LI ^{2}=\frac{5}{2}\)…
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