JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A particle of mass \( m\) moving in the \(x\) direction with speed \(2v\) is hit by another particle of mass \(2m\) moving in the \(y\) direction with speed \(v\). If the collision is perfectly inelastic, the percentage loss in the energy during the collision is close to .............. \(\%\)
- A \(50\)
- B \(56\)
- C \(62 \)
- D \(44\)
Answer & Solution
Correct Answer
(B) \(56\)
Step-by-step Solution
Detailed explanation
Initial momentum of the system \({p_i} = \sqrt {\left[ {m{{\left( {2V} \right)}^2} \times m{{\left( {2V} \right)}^2}} \right]} \) \( = \sqrt 2 m \times 2V\) Final momentum of the system\( = 3mV\) By the law of conservation of momentum \(2\sqrt 2 mv \times 3mV\)…
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