JEE Mains · Physics · STD 12 - 10. Wave optics
A parallel beam of monochromatic light of wavelength \(5000 \mathring A\) is incident normally on a single narrow slit of width \(0.001 \mathrm{~mm}\). The light is focused by convex lens on screen, placed on its focal plane. The first minima will be formed for the angle of diffraction of______________(degree).
- A \(40\)
- B \(20\)
- C \(30\)
- D \(10\)
Answer & Solution
Correct Answer
(C) \(30\)
Step-by-step Solution
Detailed explanation
For first minima \(\text { a } \sin \theta=\lambda\) \( \Rightarrow \sin \theta=\frac{\lambda}{a}=\frac{5000 \times 10^{-10}}{1 \times 10^{-6}}=\frac{1}{2} \) \( \Rightarrow \theta=30^{\circ}\)
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