JEE Mains · Maths · STD 12 - 8. Application and integration
Let \(f: \mathbf{R} \rightarrow \mathbf{R}\) be a function such that \(f(x) + 3f\left(\dfrac{\pi}{2} - x\right) = \sin x\), \(x \in \mathbf{R}\). Let the maximum value of \(f\) on \(\mathbf{R}\) be \(\alpha\). If the area of the region bounded by the curves \(g(x) = x^2\) and \(h(x) = \beta x^3\), \(\beta > 0\), is \(\alpha^2\), then \(30\beta^3\) is equal to _______.
- A 16
- B 32
- C 38
- D 40
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
Given \(f(x) + 3f\left(\dfrac{\pi}{2} - x\right) = \sin x\) Replacing \(x\) with \(\dfrac{\pi}{2} - x\), we get: \(f\left(\dfrac{\pi}{2} - x\right) + 3f(x) = \sin\left(\dfrac{\pi}{2} - x\right) = \cos x\) Multiplying this equation by \(3\) and subtracting the first equation…
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