JEE Mains · Physics · STD 12 - 10. Wave optics
Two light beams of intensities in the ratio of \(9: 4\) are allowed to interfere. The ratio of the intensity of maxima and minima will be
- A \(2: 3\)
- B \(16: 81\)
- C \(25: 169\)
- D \(25: 1\)
Answer & Solution
Correct Answer
(D) \(25: 1\)
Step-by-step Solution
Detailed explanation
\(\sqrt{\frac{I_{1}}{I_{2}}}=\sqrt{\frac{9}{4}}=\frac{3}{2}\) \(\left(\frac{\sqrt{ I _{1}}+\sqrt{ I _{2}}}{\sqrt{ I _{1}}-\sqrt{ I _{2}}}\right)^{2}=5^{2}=25\)
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