JEE Mains · Physics · STD 12 - 12. atoms
A monochromatic light is incident on a hydrogen sample in ground state. Hydrogen atoms absorb a fraction of light and subsequently emit radiation of six different wavelengths. The frequency of incident light is \(x \times 10^{15}\,Hz\). The value of \(x\) is (Given \(h =4.25 \times 10^{-15}\,eVs\) )
- A \(2\)
- B \(3\)
- C \(4\)
- D \(8\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(6={ }^4 C _2 \quad \Rightarrow n _2=4\) \(h v= E _4- E _1\) \(\therefore v=13.6\left(\frac{1}{1^2}-\frac{1}{4^2}\right) \times \frac{1}{4.25 \times 10^{-15}}\) \(=3 \times 10^{15}\,Hz\)
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