JEE Mains · Physics · STD 12 - Semicondutor electronics
- JEE Mains 2019
- Medium
- Numerical
In the given circuit the current through Zener Diode is close to.......\(mA\)

Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
\(12-500\left(2 i_{1}+i_{2}\right)-10=0\)
\(\Rightarrow \quad 2 i_{1}+i_{2}=\frac{2}{500}=\frac{1}{250}\)
\(< i_1\) when zenor has break down. \(\mathrm{So}, \mathrm{i}_{2}=0\)
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