JEE Mains · Physics · STD 12 - 11. Dual nature of radiation and matter
The threshold frequency of metal is \(f_0\). When the light of frequency \(2 f_0\) is incident on the metal plate, the maximum velocity of photoelectron is \(v_1\). When the frequency of incident radiation is increased to \(5 f _0\). the maximum velocity of photoelectrons emitted is \(v_2\). The ratio of \(v_1\) to \(v_2\) is:
- A \(\frac{v_1}{v_2}=\frac{1}{2}\)
- B \(\frac{v_1}{v_2}=\frac{1}{8}\)
- C \(\frac{v_1}{v_2}=\frac{1}{16}\)
- D \(\frac{v_1}{v_2}=\frac{1}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{v_1}{v_2}=\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(K _{\max }= hf - hf _0\) For \(f =2 f _0\) \(\frac{1}{2} m V _1^2=2 h f _0- hf _0= hf f _0\) For \(f =5 f _0\) \(\frac{1}{2} m V _2^2=5 h \textrm {f } _ { 0 } - hf _0=4 h _0\) \(\frac{ V _1}{ V _2}=\frac{1}{2}\)
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