JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
The truth table for the followng logic circuit is ...... .
- A
\(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) - B
\(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - C
\(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) - D
\(A\) \(B\) \(Y\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\)
Answer & Solution
Correct Answer
(B)
\(A\) \(B\) \(Y\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\)
Step-by-step Solution
Detailed explanation
\(y=\overline{(A \bar{B}+\bar{A} B)}\) \(y=\overline{A \bar{B}} \cdot \overline{\bar{A} B}\) \(y=(\bar{A}+B) \cdot(A+\bar{B})\) \(y=\bar{A} \cdot A+\bar{A} \bar{B}+A \cdot B+B \bar{B}\) \(y=A B+\bar{A} \bar{B}\) \(A\) \(B\) \(Y = AB +\overline{ A } \overline{ B }\) \(0\) \(0\)…
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