JEE Mains · Physics · STD 12 -6. Electromagnetic induction
An ideal transformer with purely resistive load operates at \(12\,kV\) on the primary side. It supplies electrical energy to a number of nearby houses at \(120\,V\). The average rate of energy consumption in the houses served by the transformer is \(60\,kW\). The value of resistive load (Rs) required in the secondary circuit will be \(.........\,m \Omega\).
- A \(250\)
- B \(260\)
- C \(290\)
- D \(240\)
Answer & Solution
Correct Answer
(D) \(240\)
Step-by-step Solution
Detailed explanation
\(v _{ p }=12 \times 10^3 \text { volts }\) \(v _5=120 \text { volts }\) \(p _{ s }=60\,KW = v _5 \times i _5\) \(i _5=\frac{60 \times 10^3}{120}=5 \times 10^2\,A\) \(R _{ L }=\frac{ v _5}{ i _5}=\frac{120}{5 \times 10^2}=24 \times 10^{-2}=240 \times 10^{-3} \Omega\)…
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