JEE Mains · Physics · STD 11 - 2. motion in straight line
A body travels \(102.5 \mathrm{~m}\) in \(\mathrm{n}^{\text {th }}\) second and \(115.0 \mathrm{~m}\) in \((n+2)^{\text {th }}\) second. The acceleration is what?
- A \(9 \mathrm{~m} / \mathrm{s}^2\)
- B \(6.25 \mathrm{~m} / \mathrm{s}^2\)
- C \(12.5 \mathrm{~m} / \mathrm{s}^2\)
- D \(5 \mathrm{~m} / \mathrm{s}^2\)
Answer & Solution
Correct Answer
(B) \(6.25 \mathrm{~m} / \mathrm{s}^2\)
Step-by-step Solution
Detailed explanation
Given, \(102.5=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}-1) \&\) \(115=\mathrm{u}+\frac{\mathrm{a}}{2}(2 \mathrm{n}+3)\) \(\Rightarrow 102.5=\mathrm{u}+\mathrm{an}-\frac{\mathrm{a}}{2} \&\) \(115=\mathrm{u}+\mathrm{an}+\frac{3 \mathrm{a}}{2}\)…
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