JEE Mains · Physics · STD 12 - Wave optics
- JEE Mains 2019
- Medium
- Numerical
In a Young’s double slit experiment, the slits are placed \(0.320\,mm\) apart. Light of wavelength \(\lambda = 500\,nm\) is incident on the slits. The total number of bright fringes that are observed in the angular range \( - {30^o} \le \theta \le {30^o}\) is
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Answer & Solution
Correct Answer
(D) \(641\)
Step-by-step Solution
Detailed explanation
\(\Delta X_{\max }=d \sin \theta=0.32 \sin 30=0.16\, \mathrm{mm}\)
\(\therefore n = \frac{{\Delta {X_{\max }}}}{\lambda }\)
\( = \frac{{0.16 \times {{10}^{ - 3}}}}{{500 \times {{10}^{ - 9}}}}\)
\(=\frac{0.16 \times 10^{6}}{500}=\frac{1600}{5}=320\)
Number of \(\mathrm{BFs}=(2 n+1)=641\)
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