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JEE Mains · Physics · STD 12 - Wave optics
  • JEE Mains 2019
  • Medium
  • Numerical

In a Young’s double slit experiment, the slits are placed \(0.320\,mm\) apart. Light of wavelength \(\lambda = 500\,nm\) is incident on the slits. The total number of bright fringes that are observed in the angular range \( - {30^o} \le \theta  \le {30^o}\) is

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Answer & Solution

Correct Answer

(D) \(641\)

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Detailed explanation

\(\Delta X_{\max }=d \sin \theta=0.32 \sin 30=0.16\, \mathrm{mm}\)

\(\therefore n = \frac{{\Delta {X_{\max }}}}{\lambda }\)

\( = \frac{{0.16 \times {{10}^{ - 3}}}}{{500 \times {{10}^{ - 9}}}}\)

\(=\frac{0.16 \times 10^{6}}{500}=\frac{1600}{5}=320\)

Number of  \(\mathrm{BFs}=(2 n+1)=641\)

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