Two infinite identical charged sheets and a charged spherical body of charge density ' ' are arranged as shown in figure. Then the correct relation between the electrical fields at A, B, C and D points is:

(A) \overrightarrow{\mathrm{E}}_{\mathrm{A}}=\overrightarrow{\mathrm{E}}_{\mathrm{B}} ; \overrightarrow{\mathrm{E}}_{\mathrm{C}}=\overrightarrow{\mathrm{E}}_{\mathrm{D}}

(B) \overrightarrow{\mathrm{E}}_{\mathrm{A}} \gt \overrightarrow{\mathrm{E}}_{\mathrm{B}} ; \overrightarrow{\mathrm{E}}_{\mathrm{C}}=\overrightarrow{\mathrm{E}}_{\mathrm{D}}

(D) \left|\overrightarrow{\mathrm{E}}_{\mathrm{A}}\right|=\left|\overrightarrow{\mathrm{E}}_{\mathrm{B}}\right| ; \overrightarrow{\mathrm{E}}_{\mathrm{C}} \gt \overrightarrow{\mathrm{E}}_{\mathrm{D}}

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JEE Mains · Physics · STD 12 - Electric charges and fields

JEE Mains 2025
Medium
MCQ

Two infinite identical charged sheets and a charged spherical body of charge density ' \(\rho\) ' are arranged as shown in figure. Then the correct relation between the electrical fields at \(\mathrm{A}, \mathrm{B}, \mathrm{C}\) and D points is :

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Correct Answer

(C) \(\overrightarrow{\mathrm{E}}_{\mathrm{C}} \neq \overrightarrow{\mathrm{E}}_{\mathrm{D}} ; \overrightarrow{\mathrm{E}}_{\mathrm{A}} \gt \overrightarrow{\mathrm{E}}_{\mathrm{B}}\)

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Conceptual
\(\begin{aligned}
& \mathrm{E}_{\mathrm{C}} \neq \mathrm{E}_{\mathrm{D}} \\
& \mathrm{E}_{\mathrm{A}} \gt \mathrm{E}_{\mathrm{B}}
\end{aligned}\)

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