JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
As shown in the figure, a particle of mass \(10\) \(kg\) is placed at a point \(A\). When the particle is slightly displaced to its right, it starts moving and reaches the point \(B\). The speed of the particle at \(B\) is \(x\, m / s\). (Take \(\left. g =10\, m / s ^{2}\right)\) The value of \('x'\) to the nearest integer is.........
- A \(5\)
- B \(8\)
- C \(12\)
- D \(10\)
Answer & Solution
Correct Answer
(D) \(10\)
Step-by-step Solution
Detailed explanation
Using work energy theorem, \(W _{ g }=\Delta K . E\) \((10)(g)(5)=\frac{1}{2}(10) v^{2}-0\) \(v =10 m / s\)
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