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JEE Mains · Physics · STD 11 - Kinetic theory of gases
- JEE Mains 2020
- Medium
- MCQ
Number of molecules in a volume of \(4\, cm ^{3}\) of a perfect monoatomic gas at some temperature \(T\) and at a pressure of \(2\, cm\) of mercury is close to \(?\) (Given, mean kinetic energy of a molecule (at \(T\) ) is \(4 \times 10^{-14}\) erg, \(g=980\, cm / s ^{2}\), density of mercury \(=13.6\, g / cm ^{3}\))
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(4.0 \times 10^{18}\)
Step-by-step Solution
Detailed explanation
\(n =\frac{ PV }{ RT }, \frac{3}{2} kT =4 \times 10^{-14}\)
\(N =\frac{ PV }{ RT } \times Na\)
\(=\frac{2 \times 13.6 \times 980 \times 4}{\frac{8}{3} \times 10^{-14}}=3.99 \times 10^{18}\)
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