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JEE Mains · Physics · STD 11 - 12 . kinetic theory of gases
Number of molecules in a volume of \(4\, cm ^{3}\) of a perfect monoatomic gas at some temperature \(T\) and at a pressure of \(2\, cm\) of mercury is close to \(?\) (Given, mean kinetic energy of a molecule (at \(T\) ) is \(4 \times 10^{-14}\) erg, \(g=980\, cm / s ^{2}\), density of mercury \(=13.6\, g / cm ^{3}\))
- A \(5.8 \times 10^{18}\)
- B \(5.8 \times 10^{16}\)
- C \(4.0 \times 10^{18}\)
- D \(4.0 \times 10^{16}\)
Answer & Solution
Correct Answer
(C) \(4.0 \times 10^{18}\)
Step-by-step Solution
Detailed explanation
\(n =\frac{ PV }{ RT }, \frac{3}{2} kT =4 \times 10^{-14}\) \(N =\frac{ PV }{ RT } \times Na\) \(=\frac{2 \times 13.6 \times 980 \times 4}{\frac{8}{3} \times 10^{-14}}=3.99 \times 10^{18}\)
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