JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
Two identical bodies \(A\) and \(B\) of equal masses have initial velocities \(\vec{v_1} = 4\hat{i}\) m/s and \(\vec{v_2} = 4\hat{j}\) m/s respectively. The body \(A\) has acceleration \(\vec{a_1} = 6\hat{i} + 6\hat{j}\) m/s\(^2\) while the acceleration of the other body \(B\) is zero. The centre of mass of the two bodies moves in __________ path.
- A circular
- B parabolic
- C straight line
- D elliptical
Answer & Solution
Correct Answer
(C) straight line
Step-by-step Solution
Detailed explanation
Velocity of the centre of mass is given by: \(\vec{v}_{cm} = \dfrac{m_1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}\) Since \(m_1 = m_2 = m\), we get: \(\vec{v}_{cm} = \dfrac{m(4\hat{i}) + m(4\hat{j})}{2m} = 2\hat{i} + 2\hat{j}\) m/s Acceleration of the centre of mass is given by:…
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