JEE Mains · Physics · STD 11 - 3.2 motion in plane
A shell is fired from a fixed artillery gun with an initial speed \(u\) such that it hits the target on the ground at a distance \(R\) from it. If \(t_1\) and \(t_2\) are the values of the time taken by it to hit the target in two possible ways, the product \(t_1t_2\) is
- A \(2R/g\)
- B \(R/4g\)
- C \(R/g\)
- D \(R/2g\)
Answer & Solution
Correct Answer
(A) \(2R/g\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} Range\,will\,be\,same\,for\,time\,{t_1}\,and\,{t_2},\,so\,\\ angles\,of\,projrection\,will\,be\,'\theta '\,\& '{90^ \circ } - \theta '\\ {t_1} = \frac{{2u\,\sin \,\theta }}{g}{t_2} = \frac{{2u\,\sin \,\left( {{{90}^ \circ } - \theta } \right)}}{g}\,and\\…
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