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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics
Truth table for the given circuit will be

- A
\(x\) \(y\) \(z\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) - B
\(x\) \(y\) \(z\) \(0\) \(0\) \(0\) \(0\) \(1\) \(0\) \(1\) \(0\) \(0\) \(1\) \(1\) \(1\) - C
\(x\) \(y\) \(z\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\) - D
\(x\) \(y\) \(z\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
Answer & Solution
Correct Answer
(C)
\(x\) \(y\) \(z\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(1\)
Step-by-step Solution
Detailed explanation
Truth table of the circuit is as follows \(x\) \(y\) \(\bar x\) \(a= x.y\) \(b=\bar x.y\) \(z=\bar {a.b}\) \(0\) \(0\) \(1\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(0\) \(1\)
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