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JEE Mains · Physics · STD 12 - 14. Semicondutor electronics

Truth table for the given circuit will be

  1. A
    \(x\) \(y\) \(z\)
    \(0\) \(0\) \(1\)
    \(0\) \(1\) \(1\)
    \(1\) \(0\) \(1\)
    \(1\) \(1\) \(0\)
     
  2. B
    \(x\) \(y\) \(z\)
    \(0\) \(0\) \(0\)
    \(0\) \(1\) \(0\)
    \(1\) \(0\) \(0\)
    \(1\) \(1\) \(1\)
     
  3. C
    \(x\) \(y\) \(z\)
    \(0\) \(0\) \(1\)
    \(0\) \(1\) \(1\)
    \(1\) \(0\) \(1\)
    \(1\) \(1\) \(1\)
  4. D
    \(x\) \(y\) \(z\)
    \(0\) \(0\) \(0\)
    \(0\) \(1\) \(1\)
    \(1\) \(0\) \(1\)
    \(1\) \(1\) \(1\)
Verified Solution

Answer & Solution

Correct Answer

(C)

\(x\) \(y\) \(z\)
\(0\) \(0\) \(1\)
\(0\) \(1\) \(1\)
\(1\) \(0\) \(1\)
\(1\) \(1\) \(1\)

Step-by-step Solution

Detailed explanation

Truth table of the circuit is as follows \(x\) \(y\) \(\bar x\) \(a= x.y\) \(b=\bar x.y\) \(z=\bar {a.b}\) \(0\) \(0\) \(1\) \(0\) \(0\) \(1\) \(0\) \(1\) \(1\) \(0\) \(1\) \(1\) \(1\) \(0\) \(0\) \(0\) \(0\) \(1\) \(1\) \(1\) \(0\) \(1\) \(0\) \(1\)
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