JEE Mains · Physics · STD 11 - 9.1 fluid mechanics
A metal block of base area \(0.20\,m ^2\) is placed on a table, as shown in figure. A liquid film of thickness \(0.25\,mm\) is inserted between the block and the table. The block is pushed by a horizontal force of \(0.1\,N\) and moves with a constant speed. If the viscosity of the liquid is \(5.0 \times 10^{-3} \;Pa-s\), the speed of block is \(.........\times 10^{-3}\,m / s\)
- A \(12\)
- B \(25\)
- C \(30\)
- D \(40\)
Answer & Solution
Correct Answer
(B) \(25\)
Step-by-step Solution
Detailed explanation
\(| F |=\eta A \frac{\Delta v }{\Delta h }: 0.1=5 \times 10^{-3} \times 0.2 \times \frac{ v }{.25 \times 10^{-3}}\) \(v =0.025\,m / s \text { or } v =25 \times 10^{-3}\,m / s\)
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