JEE Mains · Physics · STD 11 - 6. system of particles and rotational motion
A rectangles solid box of length \(0.3\, m\) is held horizontally, with one of its sides on the edge of a platform of height \(5\,m\). When released, it slips off the table in a very short time \(= 0.01\, s\), remaining essentially horizontal. The angle by which it would rotate when it hits the ground will be (in radians) close to:
- A \(0.5\)
- B \(0.6\)
- C \(0.02\)
- D \(0.28\)
Answer & Solution
Correct Answer
(A) \(0.5\)
Step-by-step Solution
Detailed explanation
\(Angular \,impulse = change\, in\, angular\, momentum.\) \(\tau \,\Delta t = \Delta L\) \(mg\frac{\ell }{2} \times 0.01 = \frac{{m{\ell ^2}}}{3}\omega \) \(\omega = \frac{{3g \times 0.01}}{{2\ell }} = \frac{{3 \times 10 \times 0.01}}{{2 \times 0.3}} = \frac{1}{2} = 0.5\,rad/s\)…
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