JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
Two identical blocks \(A\) and \(B\) each of mass \(m\) resting on the smooth horizontal floor are connected by a light spring of natural length \(L\) and spring constant \(K\). A third block \(C\) of mass \(m\) moving with a speed \(v\) along the line joining \(A\) and \(B\) collides with \(A\).The maximum compression in the spring is

- A \(v\sqrt{\frac{ M }{2 K }}\)
- B \(\sqrt{\frac{ mv }{2 K }}\)
- C \(\sqrt{\frac{ mv }{ K }}\)
- D \({\sqrt{\frac{ m }{2 K }}}\)
Answer & Solution
Correct Answer
(A) \(v\sqrt{\frac{ M }{2 K }}\)
Step-by-step Solution
Detailed explanation
\(C\) comes to rest \(V_{c m}\) of \(A \& B=\frac{v}{2}\) \(\Rightarrow \frac{1}{2}\) is \(v _{ ret }^{2}=\frac{1}{2} kx ^{2}\) \(x=\sqrt{\frac{\mu \times v^{2}}{k}}=\sqrt{\frac{m}{2 k}} v\)
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