JEE Mains · Physics · STD 11 - Work,energy,power and collision
- JEE Mains 2024
- Hard
- MCQ
A particle is placed at the point \(\mathrm{A}\) of a frictionless track \(A B C\) as shown in figure. It is gently pushed toward right. The speed of the particle when it reaches the point \(B\) is _______. \(\left(\right.\) Take \(g=10 \mathrm{~m} / \mathrm{s}^2\) ).
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(\sqrt{10} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
By COME
\( \mathrm{KE}_{\mathrm{A}}+\mathrm{U}_{\mathrm{A}}=\mathrm{KE}_{\mathrm{B}}+\mathrm{U}_{\mathrm{B}} \)
\( 0+\mathrm{mg}(1)=\frac{1}{2} \mathrm{mv}^2+\mathrm{mg} \times 0.5 \)
\( v=\sqrt{g}=\sqrt{10} \mathrm{~m} / \mathrm{s}\)
\( \mathrm{KE}_{\mathrm{A}}+\mathrm{U}_{\mathrm{A}}=\mathrm{KE}_{\mathrm{B}}+\mathrm{U}_{\mathrm{B}} \)
\( 0+\mathrm{mg}(1)=\frac{1}{2} \mathrm{mv}^2+\mathrm{mg} \times 0.5 \)
\( v=\sqrt{g}=\sqrt{10} \mathrm{~m} / \mathrm{s}\)
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