JEE Mains · Physics · STD 11 - 5. work,energy,power and collision
A particle is placed at the point \(\mathrm{A}\) of a frictionless track \(A B C\) as shown in figure. It is gently pushed toward right. The speed of the particle when it reaches the point \(B\) is _______. \(\left(\right.\) Take \(g=10 \mathrm{~m} / \mathrm{s}^2\) ).
- A \(20 \mathrm{~m} / \mathrm{s}\)
- B \(\sqrt{10} \mathrm{~m} / \mathrm{s}\)
- C \(2 \sqrt{10} \mathrm{~m} / \mathrm{s}\)
- D \(10 \mathrm{~m} / \mathrm{s}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{10} \mathrm{~m} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
By COME \( \mathrm{KE}_{\mathrm{A}}+\mathrm{U}_{\mathrm{A}}=\mathrm{KE}_{\mathrm{B}}+\mathrm{U}_{\mathrm{B}} \) \( 0+\mathrm{mg}(1)=\frac{1}{2} \mathrm{mv}^2+\mathrm{mg} \times 0.5 \) \( v=\sqrt{g}=\sqrt{10} \mathrm{~m} / \mathrm{s}\)
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