JEE Mains · Physics · STD 12 - Electric charges and fields
- JEE Mains 2022
- Medium
- Numerical
Two electric dipoles of dipole moments \(1.2 \times 10^{-30}\,cm\) and \(2.4 \times 10^{-30}\,cm\) are placed in two difference uniform electric fields of strengths \(5 \times 10^{4}\,NC ^{-1}\) and \(15 \times 10^{4}\,NC ^{-1}\) respectively. The ratio of maximum torque experienced by the electric dipoles will be \(\frac{1}{ x }\). The value of \(x\) is \(.....\)
Pick an option to check your answer.
Answer & Solution
Correct Answer
(A) \(6\)
Step-by-step Solution
Detailed explanation
\(|\tau|_{\max }= PE\)
\(\frac{\tau_{1}}{\tau_{2}}=\frac{ P _{1} E _{1}}{ P _{2} E _{2}}=\frac{1 \cdot 2 \times 10^{-30} \times 5 \times 10^{4}}{2 \cdot 4 \times 10^{-30} \times 15 \times 10^{4}}\)
\(=\frac{1}{6}\)
Hence \(x=6\)
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